sin 120°+3/2 cos 30°+1/3 tan (-60)°
Matematika
urqueen
Pertanyaan
sin 120°+3/2 cos 30°+1/3 tan (-60)°
1 Jawaban
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1. Jawaban nesarsiburian
[tex] \tan( - 60) = \tan(300) = \ - \sqrt{3} \\ \sin(120) = \sin(60) = \frac{1}{2} \sqrt{3} \\ \cos(30 ) = \frac{1}{2} \sqrt{3 } \\ \frac{1}{2} \sqrt{3} + \frac{1}{2} \sqrt{3} - \sqrt{3} = \sqrt{3} - \sqrt{3} = 0[/tex]