Matematika

Pertanyaan

sin 120°+3/2 cos 30°+1/3 tan (-60)°

1 Jawaban


  • [tex] \tan( - 60) = \tan(300) = \ - \sqrt{3} \\ \sin(120) = \sin(60) = \frac{1}{2} \sqrt{3} \\ \cos(30 ) = \frac{1}{2} \sqrt{3 } \\ \frac{1}{2} \sqrt{3} + \frac{1}{2} \sqrt{3} - \sqrt{3} = \sqrt{3} - \sqrt{3} = 0[/tex]

Pertanyaan Lainnya