jika g(×)= 3× + 2 dan h(× + 1)= ×+5/2×+1 rumus (g - h) (×)

[tex]g(x) = 3x + 2 \\ h(x + 1) = \frac{x + 5}{2x + 1} \\ h(x) = \frac{(x - 1) + 5}{2(x - 1) + 1} = \frac{x + 4}{2x - 1} \\ (g - h)(x) = 3x + 2 - \frac{x + 4}{2x - 1} \\ = \frac{(3x + 2)(2x - 1) - (x + 4)}{2x - 1} \\ = \frac{6 {x}^{2} + x - 2 - x - 4 }{2x - 1} = \frac{6x {}^{2} - 6}{2x - 1} [/tex]