1.f(x)=x pangkat -3 2.f(x)=akar 2x-3 3.f(x)=4x+1 per 2x-1 Konsep turunan
Matematika
angelaherwanta2
Pertanyaan
1.f(x)=x pangkat -3
2.f(x)=akar 2x-3
3.f(x)=4x+1 per 2x-1
Konsep turunan
2.f(x)=akar 2x-3
3.f(x)=4x+1 per 2x-1
Konsep turunan
1 Jawaban
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1. Jawaban Yulii24
[tex]1. \: f(x) = {x}^{ - 3} \\ {f}^{1} (x) = - 3 {x}^{ - 3 - 1} = - 3 {x}^{ - 4} \\ 2. \: f(x) = \sqrt{2x - 3} = {(2x - 3)}^{ \frac{1}{2} } \\ {f}^{1} (x) = \frac{1}{2} {(2x - 3)}^{ - \frac{1}{2} } (2) = \frac{1}{ \sqrt{2x - 3} } \\ 3. \: f(x) = \frac{4x + 1}{2x - 1} \\ {f}^{1} (x) = \frac{4(2x - 1) - 2(4x + 1)}{ {(2x - 1)}^{2} } = \frac{8x - 4 - 8x - 2}{ {(2x - 1)}^{2} } = \frac{ - 6}{ {(2x - 1)}^{2} } [/tex]