No 3, 4, 5 Aja. Tolong ya

3. Diket= jml drum = 6
r = 24
d= 24 × 2 = 48
Dit= pnjg tali minimum?
Jawab
p. tali = k. lingkaran + 6 d
= (π2r) + (6 × 48)
= (3,14 × 2 × 24) + (288)
= 150,72 + 288
= 438,72 cm

4. Diket= jml kaleng = 6
r = 10
d= 10 × 2 = 20
Dit= pnjg tali minimum?
Jawab
p.tali = k. lingkaran + 6 d
= (π2r) + (6 × 20)
= (3,14×2×10) + (120)
= 62,8 + 120
= 182,8 cm

5. Diket= jml pipa = 5
r = 3
d= 3 × 2 =6
Dit= pnjg tali minimum?
Jawab
p. tali = k. lingkaran + 5 d
= (π2r) + (5 × 6)
= (3,14×2×3) + (30)
= 18,84 + 30
= 48,84 cm