Nilai x yang memenuhi 3√25^x+=125^x-1 adalah... A. -1/3 b. -1/4 c. -1/5 d. -1/6 e. -1/7

[tex] \sqrt[3]{25 {}^{x + 4} } = 125 {}^{ x+ 1} \\ \sqrt[3]{(5 {}^{2} ) {}^{x + 4} } = (5 {}^{3} ) {}^{x + 1} \\ \sqrt[3]{ {5}^{2x + 8} } = {5}^{3x + 3} \\ {5}^{ \frac{2x + 8}{3} } = {5}^{3x + 3} \\ \frac{2x + 8}{3} = 3x + 3 \\ 2x + 8 = 9x + 9 \\ 2x - 9x = 9 - 8 \\ - 7x = 1 \\ x = - \frac{1}{7} [/tex]


semoga membantu.......