HELP ME!!! no.4,5,6 aja

4. 2√2.4 - 4√9.2 + √16.2
⇔ 4√2 - 12√2 + 4√2
⇔ -4√2 (A)

5. [tex] \frac{6}{3- \sqrt{7} } . \frac{3+ \sqrt{7} }{3+ \sqrt{7} } [/tex]
⇔ [tex] \frac{6(3+ \sqrt{7)} }{9-7} [/tex]
⇔ 3(3+√7) (A)

maaf ya kalau salah. semoga membantu

[tex]4) 2 \sqrt{8} - 4 \sqrt{18} + \sqrt{32} \\ disederhanakan = \\ 4 \sqrt{2} - 12 \sqrt{2} + 4 \sqrt{2 } \\ - 4 \sqrt{2} \\ \\ 5) \frac{6}{3 - \sqrt{7} } \times \frac{3 + \sqrt{7} }{3 + \sqrt{7} } \\ \frac{6(3 + \sqrt{7)} }{9 - 7} \\ \frac{6(3 + \sqrt{7)} }{2} \\ 3{(3 + \sqrt{7)} } [/tex]
semoga membantu