tolong... saya lupa cara ini:(

[tex] \frac{1}{3} [/tex] (2x + 1) = [tex] \frac{1}{4} [/tex] (3x - 1)

Penyelesaian:
[tex] \frac{1}{3} [/tex] . (2x + 1) = [tex] \frac{1}{4} [/tex] . (3x - 1)
[tex] \frac{(2x + 1)}{3} [/tex] = [tex] \frac{(3x - 1)}{4} [/tex]
4 (2x + 1) = 3 (3x-1)
8x + 4 = 9x -3
8x - 9x = -3 - 4
-x = -7
x = 7
nilai p + 2 = 7 + 2
                = D. 9