50 ml larutan amonia 0,5 m ditambah air 150 ml air ( Kb = 1,8 × 10-5 )
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Pertanyaan
50 ml larutan amonia 0,5 m ditambah air 150 ml air ( Kb = 1,8 × 10-5 )
1 Jawaban
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1. Jawaban tjendanayaminp4pa1h
[NH4OH]: 50×0.5/200 = 0.125 M
[OH-] = (1,8×10^-5 × 0,125)^1/2
= 1,5×10^-3
pOH= 4 - log 15
pH = 10 + log 15