Jika 1 liter larutan NH4OH 0,1 M kb Nh4Oh = 10^-5 dicampur dengan 1liyer larutan NH4CL 0,1 M. tentukan PH larutan

[tex] {oh}^{ - } = kb \times \frac{n \: basa}{n \: garam} \\ {oh}^{ - } = {10}^{ - 5} \times \frac{0.1 \times 1000}{0.1 \times 1000} \\ {oh}^{ - } = {10}^{ - 5} \\ poh = 5 \\ ph = 14 - 5 = 9[/tex]