51 gram NH3=... Liter (H=1 N=14)
            Kimia
            
               
               
            
            
               
               
             
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                Pertanyaan
            
            51 gram NH3=... Liter  (H=1 N=14)
               
            
               1 Jawaban
            
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1. Jawaban Maulanafadhli1
Mapel; Kimia
Kelas: X
Materi: Stoikiometri
Kata Kunci: Persamaan Gas ideal
Jawab
NH3
Mr (14) + (3×1)
Mr 17
M = 51/17
M= 3mol
V= mol×STP
V= 3× 22,4
V= 67,2L