Simpangan baku dari data 4,2,5,6,8,5adalah
Ujian Nasional
ulmiya
Pertanyaan
Simpangan baku dari data 4,2,5,6,8,5adalah
1 Jawaban
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1. Jawaban A17YUANISA
X = (4+2+5+6+8+5) : 2 = 30:2 = 15
Sigma (x - X)² = (4-15)² + (2-15)² + (5-15)² + (6-15)² + (8-15)² + (5-15)² = (-11)² + (-13)² + (-10)² + (-9)² + (-7)² + (-10)² = 121+169+100+81+49+100= 520
Simpangan Baku = akar 1/n.sigma(x-X)²
=Akar 1/6.520 = √86,67