carilqh varian/ragam data 8,8,6,8,6,12

[tex]x = \frac{2(6) + 3(8) + 12}{6} = \frac{48}{6} = 8 \\ ragam = \frac{2(6 - 8) {}^{2} + 3(8 - 8) {}^{2} + (12 - 8) {}^{2} }{6} = \frac{8 + 0 + 16}{6} = \frac{24}{6} = 4[/tex]