Matematika

Pertanyaan

2log2 + 2log2 + 2log7 + 2log16 - 2log28

1 Jawaban

  • ²log 2 + ²log 2 + ²log 7 + ²log 16 - ²log 28
    = ²log (2×2×7×16) : 28
    = ²log 448 : 28
    = ²log 16
    = ²log 2⁴
    = 4. ²log 2
    = 4. 1
    = 4

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