Sebuah kerucut mempunyai volume 27 cm jika diameter alas kerucut di perbesar 2kali dan tingginya di perbesar 3kali, volume kerucut yg baru adalah

[tex]V_{1} = 27 cm^{3}\\ d_{1} = d\\ d_{2} = 2d\\ t_{1} = t\\ t_{2} = 3t\\ \\ [/tex]

Ingat rumus:
[tex]V_{1} = \frac{1}{3} * \pi * (\frac{1}{d_{1}})^{2} * t_{1} \\ V_{1} = \frac{1}{3} * \pi * (\frac{1}{d})^{2} * t [/tex]

Substitusikan nanti ke:
[tex] V_{2} = \frac{1}{3} * \pi * (\frac{1}{d_{2}})^{2} * t_{2} \\ V_{2} = \frac{1}{3} * \pi * (\frac{1}{2d})^{2} * 3t \\ V_{2} = \frac{1}{3} * \pi * \frac{1}{4} * (\frac{1}{d})^{2} * 3t \\ V_{2} = \frac{3}{4} * \frac{1}{3} * \pi * (\frac{1}{d})^{2} * t \\ V_{2} = \frac{3}{4} * V_{1} \\ V_{2} = \frac{3}{4} * 27 \\ V_{2} = 20.25 cm^{3}[/tex]