- Suatu balok memiliki luas permukaan 198 cm² . Jika lebar dan tinggi balok masing-masing 6cm dan 3cm , tentukan panjang balok tersebut ? -Hitunglah perbanding

1) Lp = 2 (pl+pt+lt)
198 = 2 [(p.6)+(p.3)+(6.3)]
198 = 2(6p+3p+18)
198 = 12p + 6p + 36
198 - 36 = 12p + 6p
162 = 18p
[tex] \frac{162}{18} [/tex] = p
9 = p

2) balok1 =
Lp = 2 (pl+pt+lt)
= 2 [(6.5)+(6.4)+(5.4)]
= 2 . 74
= 148
balok2 =
Lp = 2 (pl+pt+lt)
= 2 [(3.7)+(3.4)+(7.4)]
= 2 . 61
= 122
perbandingan = 148 : 122
= 74 : 61