akar akar persamaan kuadrat2x^2+mx+16=0adalah a dan b jika a =2b dan a,b positif nilai m memenuhi adalah

a = 2B

2x² + mx + 16 = 0
a + B = -b/a = -m/2
a * B = c/a = 16/2 = 8

a * B = c/a = 16/2 = 8
2B² = 8
B² = 4
B = 2
a = 8/2 = 4

a + B = -b/a = -m/2
3B = -m/2
3(2) = -m/2
m = -12

kalau ada pertanyaan bisa ditulis di kolom komen.. sekian