Matematika

Pertanyaan

a. tan 45°,cot 60°, sec 30°
b. cos 120°, cot 150°
c. coses 240°, sin 315°
d. cos 270° tan 350°, sin 315°
e. sin 1.125°, cos 1890°, tan 2.565°, cot 3630°

1 Jawaban

  • a.
    tan 45° = 1
    cot 60° = 1/tan60° = 1/√3 = 1/3.√3
    sec 30° = 1/cos30° = 1/(1/2.√3) = 2/3.√3

    b.
    cos 120° = cos (180° - 60°) = -cos60° = -1/2
    cot 150° = 1/tan 150° = 1/tan(180°-30°) = 1/(-tan30°) = 1/(-1/3.√3) = -√3

    c.
    cosec 240° = 1/sin240° = 1/sin(180°+60°) = 1/(-sin60°) = 1/(-1/2.√3) = -2/3.√3
    sin 315° = sin (360° - 45°) = -sin45° = -1/2.√2

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