tolong bantu jawab soal no 6 dan 7
Matematika
rsyd2
Pertanyaan
tolong bantu jawab soal no 6 dan 7
1 Jawaban
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1. Jawaban pujisugiarti
[tex]3 \sqrt{ \frac{20 \times 6}{5} } = 3 \sqrt{24} = 3 \sqrt{4 \times 6} = 3 \times 2 \sqrt{6} \\ = 6 \sqrt{6} [/tex]
[tex]3 \sqrt{ \frac{20 \times 6}{5} } [/tex]