salah satu persamaan singgung melalui (a, - 1) pada lingkaran(x+3)^2+(y-2)^2 =25 adalah..... A. 4x+3y-31=0 B.4x+3y+31=0 C. 4x+3y-7=0 D.3x+4y+31 E.3x-4y-7=0 Pke

[tex] {(x + 3)}^{2} + {(y - 2)}^{2} = 25 \: \: \: \: dititik(a \: \: - 1) \\ {(a + 3)}^{2} + {( - 1 - 2)}^{2} = 25 \\ {(a + 3)}^{2} + 9 = 25 \\ a + 3 = \sqrt{16} = 4\\a = 1 \\ (x - ( - 3))(1 - ( - 3) + (y - 2)( - 1 - 2) = 25 \\ (x + 3)(4) + (y - 2)( - 3) = 25 \\ 4x + 12 - 3y + 6 = 25 \\ 4x - 3y - 7 = 0[/tex]