tentukan penyelesaian dari persamaan (y-4) (4y+3) = (2y+1)(2y-3) Tolong ya... dg cara please

(y-4)(4y+3) = (2y+1)(2y-3)
4y²+3y-16y-12 = 4y²-6y+2y-3
4y²-13y-12 = 4y²-4y-3
4y²-4y²-13y+4y = -3+12
-9y = 9
9 = 9y
y = 9 : 9
y = 1

[tex](y - 4)(4y + 3) = (2y + 1)(2y - 3) \\ < = > {4y}^{2} + 3y - 16y - 12 = {4y}^{2} - 6y + 2y - 3 \\ < = > {4y}^{2} - 13y - 12 = {4y}^{2} - 4y - 3 \\ < = > {4y}^{2} - {4y}^{2} - 13y + 4y = - 3 + 12 \\ < = > - 9y = 9 \\ < = > y = \frac{9}{-9} \\ < = > y = - 1[/tex]