(x-4)3 (x+6)4 caranya gimana?

pelajaran: segitiga pascal
kelas: xi
kata kunci: segitiga pascal

jawab:
(x+y)¹=x+y----> 1 1
(x+y)²=x²+2xy+y²------>1 2 1
(x+y)³=(x+y) x²+2xy+y²=x³+2x²y+xy²+x²y+2xy²+y³=x³+2x²y+x²y+xy²+2xy²+y³=x³+3x²y+3xy²+y³---------> 1 3 3 3 1
dan seterusnya.....

jadi
(x-4)³=(x-4) x²-8x+16=
x³-8x²+16x-4x²+32x-64= x³-8x²-4x²+16x+32x+64=
x³-12x²+48x+64

(x+6)⁴=(x+6) x³+18x²+108x+216=
x⁴+18x³+108x²+216x+6x³+108x²+648x+1296=
x⁴+18x³+6x³+108x²+108x²+216x+648x+1296=
x⁴+24x³+216x²+864x+1296