jika n=16^3×12^2/24^5,nilai 27n =

[tex]n = \frac{ {16}^{3}. {12}^{2} }{ {24}^{5} } \\ = \frac{( {2}^{4} ) {}^{3} . {2}^{4} . {3}^{2}}{ {2}^{15}. {3}^{5} } = {2}^{12} . {2}^{ - 15} . {2}^{4} . {3}^{2} . {3}^{ - 5} \\ = {2 }^{ 1} . {3}^{ - 3} = \frac{2}{ {3}^{3} } \\ 27n = {3}^{3} \times \frac{2}{ {3}^{3} } = 2[/tex]