Matematika

Pertanyaan

sederhanakan
a.√500
b.√405
c.√96

1 Jawaban

  • [tex]\sqrt{500}=\sqrt{100\times 5}=\sqrt{100}\times\sqrt{5}=10\sqrt{5} \\ \\ \sqrt{405}=\sqrt{81\times 5}=\sqrt{81}\times\sqrt{5}=9\sqrt{5} \\ \\ \sqrt{96}=\sqrt{16\times 6}=\sqrt{16}\times\sqrt{6}=4\sqrt{6}[/tex]

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