Hitunglah pH dari larutan CH3COONa 1 M (Ka CH3COOH=10^-5)

CH3COONa -> CH3COO^+ + Na^-
1M 1M 1M
Na^- + H2O -> tidak terhidrolisis
CH3COO^+ + H2O -> CH3COOH + OH^-
[OH^-] = √ kw/ka × anion
= √ 10^-14/10^-5 × 1
= √ 10^-9
=1.10^-4,5

pOH = -log [OH-]
= -log 10^-4,5
= 4,5
ph = 14 - pOH
= 14-4,5
= 9,5